Suppose $K/F$ is Galois and of degree $p^m$ where $p$ is a prime of course. Then how can we see that we have an extension $F_0 = F \subsetneq F_1 \subsetneq \cdots \subsetneq F_m = K$ such that $[F...
p(x) is a n-degree polynomial and it is orthogonal to all polynomial that has degree m (m<n) or less with respect to the inner product $<f,g>=\int_a^bf(x)g(x)w(x)dx$, where w(x)>0, cont...
The generating degree gdeg(A) of a topological commutative ring A with char A = 0 is the... Z[M] is dense in A. For a prime number p, C p denotes the topological completion of an algebraic...
Maine Law’s J.D./M.P.P.M. dual degree program with the University of Southern Maine's Muskie School of Public Service is an accelerated program that allows students to obtain a Juris Doctor (J.D.)...
Let $M,N$ be connected oriented manifolds such that $\partial M=\partial N=\emptyset$. Let $F:M\to N $ be a smooth proper map (i.e. for every $K\subset N$ compact, $F^{-1}(K)$ is compact). We defin...
I read this proposition from Lahtonen's comments here and I wish to make a proof for that. Let $p$ be a prime and $f$ be a irreducible polynomial of degree $m$ over $\Bbb{F}_p$. Then $f$ remains
I read somewhere that if $\pi$ is an irreducible polynomial of degree $m$ then $F_p(x)\ \backslash \left< \pi \right>$ is a finite field of order $p$. What is $F_p(x)\ \backslash \left< \pi \
We consider $F=\mathbb F_p$ for $p$ prime, $f(x)$ an irreducible polynomial of degree $m$ over $F$ and $g(x)=x^{p^m}-x$. I want to show that $f(x)\mid g(x)$. From the fact that the field $A=F[x]/...
The Doctor of Medicine/Master of Public Health degree (M.D./M.P.H.) is a collaboration between UT Southwestern and UTHealth School of Public Health.
Maine Law’s J.D./M.P.H dual degree program with the University of Southern Maine's Muskie School of Public Service is an accelerated program that allows students to obtain a Juris Doctor (J.D.) deg...